A simple pendulum was used by a student to determine the acceleration due to gravity, g, she obtained the following values: L = 80.0 cm,...

      

A simple pendulum was used by a student to determine the acceleration due to gravity, g, she obtained the following values: L = 80.0 cm, the period T was 1.9s. given that T=2π√(l/g) determine the value of g correct to two significant figures.

  

Answers


joseph
T=2pv(l/g)
T^2=(2p)^2(l/g)
1.92 =4p^2((.80)/g)
g= 8.75 m/s^2

joseph rimiru answered the question on October 6, 2017 at 20:06


Next: Write an essay on the relevance of title, The River and the source by Margaret Ogolla
Previous: A lawn tennis ball of mass 300 g is thrown vertically upwards with a vertically of 10 m/s. The air cause a resistance of 10...

View More Physics Questions and Answers | Return to Questions Index


Exams With Marking Schemes

Related Questions