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A wheelbarrow of mass 50 kg was pushed along a horizontal path by a horizontal force of 10 N and moves with a constant velocity....

      

A wheelbarrow of mass 50 kg was pushed along a horizontal path by a horizontal force of 10 N and moves with a constant velocity. The force was then increased to 18N. Determine :
a. The resistance to the motion of the wheelbarrow
b. The acceleration of the wheelbarrow.

  

Answers


joseph
a. Resistance = 10N
b. 18 – 10 = 8N
F = ma
8N = 50 x a
=0.16 m/s^2

joseph rimiru answered the question on October 9, 2017 at 13:57


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