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A battery of e.m.f 12 v and negligible resistance is connected to a 8 ohms resistor. How much power is dissipated by the resistor?

      

A battery of e.m.f 12 v and negligible resistance is connected to a 8 ohms resistor. How much power is dissipated by the resistor?

  

Answers


joseph
P = V^2/R
P = 12^2/8
P = 18 w

joseph rimiru answered the question on October 10, 2017 at 20:23


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