In an experiment, sulphur (IV) oxide gas was bubbled into water followed by chlorine gas. The resulting clear solution gave a white precipitate when mixed with acidified barium chloride solution

      

In an experiment, sulphur (IV) oxide gas was bubbled into water followed by chlorine gas. The resulting clear solution gave a white precipitate when mixed with acidified barium chloride solution. Explain these observations.

  

Answers


John
Sulphur (IV) oxide reacts with water to form sulphite ion which then is oxidized by chlorine to sulphate ion. The sulphate ion then reacts with barium ions to form insoluble barium sulphate
johnmulu answered the question on February 6, 2017 at 14:13


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