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Calculate the mass of product that would be formed when 200 cm3 of hydrogen chloride gas reacts completely with excess ammonia gas

      

Calculate the mass of product that would be formed when 200 cm3 of hydrogen chloride gas reacts completely with excess ammonia gas. (H = 1.0, N = 14.0, Cl = 35.5, one mole of gas occupies 24 litres at room temperatures and pressure)

  

Answers


John

HCl(g) + NH3(g) $\rightarrow$ NH4Cl(s)

Moles of HCl = $\frac{200}{2400}$ = 0.00833 moles HCl

0.00833 moles HCl = 0.00833 moles NH4Cl (ratio is 1:1)

NH4Cl = 14 + 4 + 35.5 = 53.5

0.00833 X 53.5 = 0.446 g
johnmulu answered the question on February 7, 2017 at 09:55


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