HCl(g) + NH3(g) $\rightarrow$ NH4Cl(s)
Moles of HCl = $\frac{200}{2400}$ = 0.00833 moles HCl
0.00833 moles HCl = 0.00833 moles NH4Cl (ratio is 1:1)
NH4Cl = 14 + 4 + 35.5 = 53.5
0.00833 X 53.5 = 0.446 g
johnmulu answered the question on February 7, 2017 at 09:55
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