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i) HCL(aq) + NaOH(aq) $\rightarrow$ NaCl(aq) + H2Ol
Moles of NaOH = Moles of HCL
= $\frac{46 \times 11}{1000}$ = 0.506 moles
ii) Moles of HCL in 250cm3 = 0.506 $\times$ 10 = 5.06
R.M.M of HCL = 1 + 35.5 = 36.5
Mass of HCL = 5.06 $\times$ 36.5
= 184.69g
johnmulu answered the question on February 9, 2017 at 09:23
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