2.2 +5.1 +8.16 +11.35 = 26.81 mm.
joseph rimiru answered the question on October 17, 2017 at 12:28
- Evaluate without the use of a calculator.
a. (3.35 + 8.5) –(3.56 +2.67)
b. 12.12 –[(6.35 +7.43) – 2.88]
c. 16.21 –(3.7 -4.1) -5.3
d. 46.13 – [(6.44 -2.27)- 9.1]
(Solved)
Evaluate without the use of a calculator.
a. (3.35 + 8.5) –(3.56 +2.67)
b. 12.12 –[(6.35 +7.43) – 2.88]
c. 16.21 –(3.7 -4.1) -5.3
d. 46.13 – [(6.44 -2.27)- 9.1]
Date posted: October 17, 2017. Answers (1)
- Evaluate
a. 333 + 33.033 - 35.333
b. 8.942 +11.021-22.006
c. 0.358 -0.099 +3.0004
d. 16.805 – 17.579 +0.608
(Solved)
Evaluate
a. 333 + 33.033 - 35.333
b. 8.942 +11.021-22.006
c. 0.358 -0.099 +3.0004
d. 16.805 – 17.579 +0.608
Date posted: October 17, 2017. Answers (1)
- Without using the calculator evaluate the following;
a. 2.55 – 1.302
b. 39.331 – 3.978
c. 425.631- 0.004
d. 0.035 --.0085
(Solved)
Without using the calculator evaluate the following;
a. 2.55 – 1.302
b. 39.331 – 3.978
c. 425.631- 0.004
d. 0.035 --.0085
Date posted: October 17, 2017. Answers (1)
- Evaluate the following
a. 0.0014 + 0.00014 + 0.014
b. 452.4 +17.294 + 8.12
c. 42.57 + 0.293 +7.2500
d. 400.02 + 0.006 +93.3
(Solved)
Evaluate the following
a. 0.0014 + 0.00014 + 0.014
b. 452.4 +17.294 + 8.12
c. 42.57 + 0.293 +7.2500
d. 400.02 + 0.006 +93.3
Date posted: October 17, 2017. Answers (1)
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A designer used 2.25 m of material to make a dress, 1.90m, for a skirt and 0.85m for a blouse. How much cloth did she use?
Date posted: October 17, 2017. Answers (1)
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a. 1.373 + 2.009 =
b. 3.55 + 6-08 =
c. 16.85 + 0.1694 =
d. 0.0158 + 93.141 =
(Solved)
Without using a calculate evaluate
a. 1.373 + 2.009 =
b. 3.55 + 6-08 =
c. 16.85 + 0.1694 =
d. 0.0158 + 93.141 =
Date posted: October 17, 2017. Answers (1)
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a. 37 b. 676 ...(Solved)
Write each of the following in standard form
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Date posted: October 17, 2017. Answers (1)
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3/5 , 4/10, 7/5, 5/11
(Solved)
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3/5 , 4/10, 7/5, 5/11
Date posted: October 17, 2017. Answers (1)
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A deep freezer temperature was maintained at -5 ⁰C while the room temperature was 25⁰ C. what was the temperature difference?
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a. 13 +7÷ 2 – 34 =
b. 24 ÷ 8 + 4 X 5-8 ÷ 4 x 10 +...(Solved)
Evaluate the without using a calculator
a. 13 +7÷ 2 – 34 =
b. 24 ÷ 8 + 4 X 5-8 ÷ 4 x 10 + 2 =
c. -5 x 9 + 7 -12÷ 3 -5 =
d. -9 x 41 + 36÷ 9 + 12 x 12 =
Date posted: October 17, 2017. Answers (1)
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2 x (15 ÷ 5 ) =
(6 x 12 ) ÷ 9 =
(-39÷ 13) – 10 =
-84÷ (7 x 2) =
(Solved)
Evaluate the following
2 x (15 ÷ 5 ) =
(6 x 12 ) ÷ 9 =
(-39÷ 13) – 10 =
-84÷ (7 x 2) =
Date posted: October 17, 2017. Answers (1)
- Evaluate the following
a. 73 – 31 + 26 =
b. 3005 – 563 + 1044 =
c. 349 + 60 – 510 =
d. 87 – 110 + 5 =
(Solved)
Evaluate the following
a. 73 – 31 + 26 =
b. 3005 – 563 + 1044 =
c. 349 + 60 – 510 =
d. 87 – 110 + 5 =
Date posted: October 17, 2017. Answers (1)
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a. (19 – 25) + 31 =
b. (75 – 25) + 180 =
c. (78 + 55) – 101 =
d. 85 – (101 + 3) =
(Solved)
Evaluate each of the following
a. (19 – 25) + 31 =
b. (75 – 25) + 180 =
c. (78 + 55) – 101 =
d. 85 – (101 + 3) =
Date posted: October 17, 2017. Answers (1)
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a. ¼ b. 5/8 c. 5/23
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a. ¼ b. 5/8 c. 5/23
Date posted: October 16, 2017. Answers (1)
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a. One third b. one eighth c. Two fifth d. seven hundredth
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Date posted: October 16, 2017. Answers (1)
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616, 634,...(Solved)
Ten casual laborers were hired by a sisal factory for one week and paid in shillings, according to productive of each, as shown below:
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Date posted: October 16, 2017. Answers (1)