(3.0 + 5.0 +4.5 +7.5) x sh 50 =sh 1000
joseph rimiru answered the question on October 17, 2017 at 12:30
- A botanist measured the growth of a seedling 5 cm high every week. The increase in growth in four weeks were 2.2 mm, 5.1 mm,...(Solved)
A botanist measured the growth of a seedling 5 cm high every week. The increase in growth in four weeks were 2.2 mm, 5.1 mm, 8.16mm and 11.35 mm. what was the total increase in length of the seedling?
Date posted: October 17, 2017. Answers (1)
- Evaluate without the use of a calculator.
a. (3.35 + 8.5) –(3.56 +2.67)
b. 12.12 –[(6.35 +7.43) – 2.88]
c. 16.21 –(3.7 -4.1) -5.3
d. 46.13 – [(6.44 -2.27)- 9.1]
(Solved)
Evaluate without the use of a calculator.
a. (3.35 + 8.5) –(3.56 +2.67)
b. 12.12 –[(6.35 +7.43) – 2.88]
c. 16.21 –(3.7 -4.1) -5.3
d. 46.13 – [(6.44 -2.27)- 9.1]
Date posted: October 17, 2017. Answers (1)
- Evaluate
a. 333 + 33.033 - 35.333
b. 8.942 +11.021-22.006
c. 0.358 -0.099 +3.0004
d. 16.805 – 17.579 +0.608
(Solved)
Evaluate
a. 333 + 33.033 - 35.333
b. 8.942 +11.021-22.006
c. 0.358 -0.099 +3.0004
d. 16.805 – 17.579 +0.608
Date posted: October 17, 2017. Answers (1)
- Without using the calculator evaluate the following;
a. 2.55 – 1.302
b. 39.331 – 3.978
c. 425.631- 0.004
d. 0.035 --.0085
(Solved)
Without using the calculator evaluate the following;
a. 2.55 – 1.302
b. 39.331 – 3.978
c. 425.631- 0.004
d. 0.035 --.0085
Date posted: October 17, 2017. Answers (1)
- Evaluate the following
a. 0.0014 + 0.00014 + 0.014
b. 452.4 +17.294 + 8.12
c. 42.57 + 0.293 +7.2500
d. 400.02 + 0.006 +93.3
(Solved)
Evaluate the following
a. 0.0014 + 0.00014 + 0.014
b. 452.4 +17.294 + 8.12
c. 42.57 + 0.293 +7.2500
d. 400.02 + 0.006 +93.3
Date posted: October 17, 2017. Answers (1)
- A designer used 2.25 m of material to make a dress, 1.90m, for a skirt and 0.85m for a blouse. How much cloth did she...(Solved)
A designer used 2.25 m of material to make a dress, 1.90m, for a skirt and 0.85m for a blouse. How much cloth did she use?
Date posted: October 17, 2017. Answers (1)
- Without using a calculate evaluate
a. 1.373 + 2.009 =
b. 3.55 + 6-08 =
c. 16.85 + 0.1694 =
d. 0.0158 + 93.141 =
(Solved)
Without using a calculate evaluate
a. 1.373 + 2.009 =
b. 3.55 + 6-08 =
c. 16.85 + 0.1694 =
d. 0.0158 + 93.141 =
Date posted: October 17, 2017. Answers (1)
- Write each of the following in standard form
a. 37 b. 676 ...(Solved)
Write each of the following in standard form
a. 37 b. 676 c. 0.073 d. 0.0085
Date posted: October 17, 2017. Answers (1)
- Arrange the following in descending order
3/5 , 4/10, 7/5, 5/11
(Solved)
Arrange the following in descending order
3/5 , 4/10, 7/5, 5/11
Date posted: October 17, 2017. Answers (1)
- The temperature of a patient was 41°C when admitted to a hospital. After treatment it stabilized at 37.1°C. Find the change in temperature(Solved)
The temperature of a patient was 41⁰C when admitted to a hospital. After treatment it stabilized at 37.1⁰C. Find the change in temperature
Date posted: October 17, 2017. Answers (1)
- The town of Kericho is found on the Kisumu – Nakuru highway. The distance between Kisumu and kericho is 86 km, while that between...(Solved)
The town of Kericho is found on the Kisumu – Nakuru highway. The distance between Kisumu and kericho is 86 km, while that between Kericho and Nakuru is 106 km. what is the distance between Nakuru and Kisumu?
Date posted: October 17, 2017. Answers (1)
- A boy used the stairs down four floors from the ninth floor and then took a lift to the twentieth floor....(Solved)
A boy used the stairs down four floors from the ninth floor and then took a lift to the twentieth floor. How many floors did he go through while in the lift?
Date posted: October 17, 2017. Answers (1)
- A deep freezer temperature was maintained at -5 °C while the room temperature was 25° C. what was the temperature difference?(Solved)
A deep freezer temperature was maintained at -5 ⁰C while the room temperature was 25⁰ C. what was the temperature difference?
Date posted: October 17, 2017. Answers (1)
- Evaluate the without using a calculator
a. 13 +7÷ 2 – 34 =
b. 24 ÷ 8 + 4 X 5-8 ÷ 4 x 10 +...(Solved)
Evaluate the without using a calculator
a. 13 +7÷ 2 – 34 =
b. 24 ÷ 8 + 4 X 5-8 ÷ 4 x 10 + 2 =
c. -5 x 9 + 7 -12÷ 3 -5 =
d. -9 x 41 + 36÷ 9 + 12 x 12 =
Date posted: October 17, 2017. Answers (1)
- Evaluate the following
2 x (15 ÷ 5 ) =
(6 x 12 ) ÷ 9 =
(-39÷ 13) – 10 =
-84÷ (7 x 2) =
(Solved)
Evaluate the following
2 x (15 ÷ 5 ) =
(6 x 12 ) ÷ 9 =
(-39÷ 13) – 10 =
-84÷ (7 x 2) =
Date posted: October 17, 2017. Answers (1)
- Evaluate the following
a. 73 – 31 + 26 =
b. 3005 – 563 + 1044 =
c. 349 + 60 – 510 =
d. 87 – 110 + 5 =
(Solved)
Evaluate the following
a. 73 – 31 + 26 =
b. 3005 – 563 + 1044 =
c. 349 + 60 – 510 =
d. 87 – 110 + 5 =
Date posted: October 17, 2017. Answers (1)
- Evaluate each of the following
a. (19 – 25) + 31 =
b. (75 – 25) + 180 =
c. (78 + 55) – 101 =
d. 85 – (101 + 3) =
(Solved)
Evaluate each of the following
a. (19 – 25) + 31 =
b. (75 – 25) + 180 =
c. (78 + 55) – 101 =
d. 85 – (101 + 3) =
Date posted: October 17, 2017. Answers (1)
- Write each of the following fraction in words
a. ¼ b. 5/8 c. 5/23
(Solved)
Write each of the following fraction in words
a. ¼ b. 5/8 c. 5/23
Date posted: October 16, 2017. Answers (1)
- Write the following in numerals
a. One third b. one eighth c. Two fifth d. seven hundredth
(Solved)
Write the following in numerals
a. One third b. one eighth c. Two fifth d. seven hundredth
Date posted: October 16, 2017. Answers (1)
- In a bakery, the mass of 30 cakes taken at random is 20 kg. If the mean of the first 12 is 400 g, find...(Solved)
In a bakery, the mass of 30 cakes taken at random is 20 kg. If the mean of the first 12 is 400 g, find the mean of the mass of the other 18 cakes.
Date posted: October 16, 2017. Answers (1)