AC = OC - OA
$ \begin{pmatrix}
2 \\
4 \\
5
\end{pmatrix} - \begin{pmatrix}
2 \\
5 \\
4
\end{pmatrix} = \begin{pmatrix}
0 \\
-1 \\
1
\end{pmatrix}$
CB = OB - OC
$ \begin{pmatrix}
2 \\
1 \\
8
\end{pmatrix} - \begin{pmatrix}
2 \\
4 \\
5
\end{pmatrix} = \begin{pmatrix}
0 \\
-3 \\
3
\end{pmatrix}$
AC = kCB
$ \begin{pmatrix}
0 \\
-1 \\
4
\end{pmatrix} =k \begin{pmatrix}
0 \\
-3 \\
3
\end{pmatrix}$
k =$\frac{1}{3}$
AC = $\frac{1}{3}CB$
AC:CB = 1:3
raphael answered the question on January 14, 2017 at 07:28
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