a. 23.28
b. 463.167
c. 28.980
d. 44.0063632
joseph rimiru answered the question on October 18, 2017 at 09:13
- Evaluate (a) 0.15 x 0.05 = (b) 0.703 x 0.04 = (c) 0.0352 x 0.0403 = (d)0.00785 x 0.331 =(Solved)
Evaluate
a. 0.15 x 0.05 =
b. 0.703 x 0.04 =
c. 0.0352 x 0.0403 =
d. 0.00785 x 0.331 =
Date posted: October 18, 2017. Answers (1)
- Evaluate (a)3.4 x 5 = (b) 44 x 0.206 = (d) 295 x 36.04 = (d) 39.6 x 6.21 =(Solved)
Evaluate
a. 3.4 x 5 =
b. 44 x 0.206 =
c. 295 x 36.04 =
d. 39.6 x 6.21 =
Date posted: October 18, 2017. Answers (1)
- Evaluate each of the following. Show your working.a. 0.6 x 0.8 (b) 0.3 x 0.15 (c) 3.15 x 0.02 (d) 0.2 x 1.06 x 3.25(Solved)
Evaluate each of the following. Show your working.
a. 0.6 x 0.8
b. 0.3 x 0.15
c. 3.15 x 0.02
d. 0.2 x 1.06 x 3.25
Date posted: October 18, 2017. Answers (1)
- Three plastic jugs of capacity 0.85 litres, 0.79 litres, and 0.95 litres are filled using a container holding 4.5 litres of milk. How much milk...(Solved)
Three plastic jugs of capacity 0.85 litres, 0.79 litres, and 0.95 litres are filled using a container holding 4.5 litres of milk. How much milk was left on the container?
Date posted: October 18, 2017. Answers (1)
- The distance between two towns A and C is 72.7 km. If town B is between A and C and is 52.7 km from C...(Solved)
The distance between two towns A and C is 72.7 km. If town B is between A and C and is 52.7 km from C how far is B from A
Date posted: October 18, 2017. Answers (1)
- If the total mass of two pigs and 15 goats is found to be 400 kg. The two pigs’ mass was 150kg, the find...(Solved)
If the total mass of two pigs and 15 goats is found to be 400 kg. The two pigs’ mass was 150kg, the find the average mass of the each of the goat.
Date posted: October 18, 2017. Answers (1)
- A wood cutter had logs which measured 5.4 m, 0.048 m, 0.34 m, 0.038 m, and 0.02 m long all from a single beam. How...(Solved)
A wood cutter had logs which measured 5.4 m, 0.048 m, 0.34 m, 0.038 m, and 0.02 m long all from a single beam. How long was the beam of wood?
Date posted: October 18, 2017. Answers (1)
- A woman spent 0.35 of her income on bills, 0.55 of the remainder on food and saved the rest. What fraction of her income did...(Solved)
A woman spent 0.35 of her income on bills, 0.55 of the remainder on food and saved the rest. What fraction of her income did she save?
Date posted: October 17, 2017. Answers (1)
- A rectangular farm is 1.52 km in length and it breadth is 0.68 km. what is the perimeter of the farm?(Solved)
A rectangular farm is 1.52 km in length and it breadth is 0.68 km. what is the perimeter of the farm?
Date posted: October 17, 2017. Answers (1)
- Four students bought 3.0 litres, 5.0 litres, 4.5 litres and 7.5 litres of milk from a dairy farm. If one litre of milk costs sh....(Solved)
Four students bought 3.0 litres, 5.0 litres, 4.5 litres and 7.5 litres of milk from a dairy farm. If one litre of milk costs sh. 50 how much money did they pay altogether?
Date posted: October 17, 2017. Answers (1)
- A botanist measured the growth of a seedling 5 cm high every week. The increase in growth in four weeks were 2.2 mm, 5.1 mm,...(Solved)
A botanist measured the growth of a seedling 5 cm high every week. The increase in growth in four weeks were 2.2 mm, 5.1 mm, 8.16mm and 11.35 mm. what was the total increase in length of the seedling?
Date posted: October 17, 2017. Answers (1)
- Evaluate without the use of a calculator.
a. (3.35 + 8.5) –(3.56 +2.67)
b. 12.12 –[(6.35 +7.43) – 2.88]
c. 16.21 –(3.7 -4.1) -5.3
d. 46.13 – [(6.44 -2.27)- 9.1]
(Solved)
Evaluate without the use of a calculator.
a. (3.35 + 8.5) –(3.56 +2.67)
b. 12.12 –[(6.35 +7.43) – 2.88]
c. 16.21 –(3.7 -4.1) -5.3
d. 46.13 – [(6.44 -2.27)- 9.1]
Date posted: October 17, 2017. Answers (1)
- Evaluate
a. 333 + 33.033 - 35.333
b. 8.942 +11.021-22.006
c. 0.358 -0.099 +3.0004
d. 16.805 – 17.579 +0.608
(Solved)
Evaluate
a. 333 + 33.033 - 35.333
b. 8.942 +11.021-22.006
c. 0.358 -0.099 +3.0004
d. 16.805 – 17.579 +0.608
Date posted: October 17, 2017. Answers (1)
- Without using the calculator evaluate the following;
a. 2.55 – 1.302
b. 39.331 – 3.978
c. 425.631- 0.004
d. 0.035 --.0085
(Solved)
Without using the calculator evaluate the following;
a. 2.55 – 1.302
b. 39.331 – 3.978
c. 425.631- 0.004
d. 0.035 --.0085
Date posted: October 17, 2017. Answers (1)
- Evaluate the following
a. 0.0014 + 0.00014 + 0.014
b. 452.4 +17.294 + 8.12
c. 42.57 + 0.293 +7.2500
d. 400.02 + 0.006 +93.3
(Solved)
Evaluate the following
a. 0.0014 + 0.00014 + 0.014
b. 452.4 +17.294 + 8.12
c. 42.57 + 0.293 +7.2500
d. 400.02 + 0.006 +93.3
Date posted: October 17, 2017. Answers (1)
- A designer used 2.25 m of material to make a dress, 1.90m, for a skirt and 0.85m for a blouse. How much cloth did she...(Solved)
A designer used 2.25 m of material to make a dress, 1.90m, for a skirt and 0.85m for a blouse. How much cloth did she use?
Date posted: October 17, 2017. Answers (1)
- Without using a calculate evaluate
a. 1.373 + 2.009 =
b. 3.55 + 6-08 =
c. 16.85 + 0.1694 =
d. 0.0158 + 93.141 =
(Solved)
Without using a calculate evaluate
a. 1.373 + 2.009 =
b. 3.55 + 6-08 =
c. 16.85 + 0.1694 =
d. 0.0158 + 93.141 =
Date posted: October 17, 2017. Answers (1)
- Write each of the following in standard form
a. 37 b. 676 ...(Solved)
Write each of the following in standard form
a. 37 b. 676 c. 0.073 d. 0.0085
Date posted: October 17, 2017. Answers (1)
- Arrange the following in descending order
3/5 , 4/10, 7/5, 5/11
(Solved)
Arrange the following in descending order
3/5 , 4/10, 7/5, 5/11
Date posted: October 17, 2017. Answers (1)
- The temperature of a patient was 41°C when admitted to a hospital. After treatment it stabilized at 37.1°C. Find the change in temperature(Solved)
The temperature of a patient was 41⁰C when admitted to a hospital. After treatment it stabilized at 37.1⁰C. Find the change in temperature
Date posted: October 17, 2017. Answers (1)