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A bullet moving at a velocity of 300 ms-1 hits a tree trunk of diameter 50 cm. It emerges from the opposite side with a velocity of 150 ms-1

      

A bullet moving at a velocity of 300 ms-1 hits a tree trunk of diameter 50 cm. It emerges from the opposite side with a velocity of 150 ms-1. Determine the average deceleration of the bullet in the trunk.

  

Answers


John
v2 = u2 + 2as $\rightarrow$ a = $\frac{v^2 - u^2}{2\times 0.5}$ = -67, 500 m/s2
johnmulu answered the question on February 13, 2017 at 06:23


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