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i) The bullet will land on the track because it has the same horizontal velocity as the track.
ii) From S = ut + $\frac{1}{2}gt^2$
For a free fall u = 0, $
\rightarrow$ s = $\frac{1}{2}gt^2$
45 = $\frac{1}{2}$ x 10 x t2
t = 3 sec,
total time = 3 x 2 = 6 sec
Horizontal distance = v x t = 50 x 6 = 300 m
johnmulu answered the question on February 14, 2017 at 06:51
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