A 4 ohm resistor is connected in series to a battery of e.m.f. 6 V and negligible internal resistance. Determine the power dissipated by the resistor.

      

A 4 ohm resistor is connected in series to a battery of e.m.f. 6 V and negligible internal resistance. Determine the power dissipated by the resistor.

  

Answers


John
P = V2R

= 6×64

= 9 Watts
johnmulu answered the question on February 15, 2017 at 13:21


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