When a current of 1.5 amperes was passed through a cell containing M3+ ions of metal M for 15 minutes, the mass of the cathode increases by 0.26 g. (1 Faraday = 96500 coulombs).

      

When a current of 1.5 amperes was passed through a cell containing M3+ ions of metal M for 15 minutes, the mass of the cathode increases by 0.26 g. (1 Faraday = 96500 coulombs).
a) Calculate the quantity of electricity used
b) Determine the relative atomic mass of metal M.

  

Answers


John
a) Q = 1.5 x 15 x 60 C

= 1350 C

b) 1350 C $\rightarrow$ 0.26 g of M

(3 x 96500)C $\rightarrow$

= $\frac{0.26\times 3\times x 96500}{1350}$

= 55.76
johnmulu answered the question on February 16, 2017 at 05:38


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Previous: An element P has a relative atomic mass of 88. When a current of 0.5 amperes was passed through the fused chloride of P for 32 minutes and 10 seconds, 0.44 g of P were deposited at the cathode.

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