a) 4OH-(aq) $\rightarrow$ 4e + 2H2O(l) + O2(g)
b) Q = It
= 5 x 3 x 60 x 60 = 54000 C
Mass of silver deposited = $\frac{108\times 54000}{96500}$
= 60.44 g
johnmulu answered the question on February 16, 2017 at 06:55
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