A long horizontal capillary tube of uniform bore sealed at one end contains dry air trapped by a drop of mercury. The length of the air column is 142 mm at 17^oC.

      

A long horizontal capillary tube of uniform bore sealed at one end contains dry air trapped by a drop of mercury. The length of the air column is 142 mm at 17^oC. Determine the length of the air column at 25^oC.

  

Answers

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V₁ = 142 mm,

T₁ = 273 + 17 = 290,

V₂ = ? T₂ = 298

$\frac{V_1}{T_1}$ = $\frac{V_2}{T_2}$ = $\frac{142}{290}$ = $\frac{V_2}{298}$

V₂ = $\frac{298\times 142}{290}$ = 145.92 mm.

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johnmulu answered the question on February 18, 2017 at 08:48

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