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A block of glass of mass 250 g floats in mercury. What volume of glass lies under the surface of the mercury? (Density of mercury is 13.6 x 103Kgm-3)

      

A block of glass of mass 250 g floats in mercury. What volume of glass lies under the surface of the mercury? (Density of mercury is 13.6 x 103Kgm-3)

  

Answers


John
Weight of block = weight of mercury displaced

0.25 x 10 = 13.6 x 103 x V

V = $\frac{0.25}{13.6\times 10^3}$ = 1.838 x 10-5m3

= 18.38 cm3
johnmulu answered the question on February 18, 2017 at 09:56


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