Calculate the time in minutes required to deposit 1.184 g of copper if a current of 2 amperes was used. (1 Faraday = 96500 coulombs, Cu = 63.5).

      

Calculate the time in minutes required to deposit 1.184 g of copper if a current of 2 amperes was used. (1 Faraday = 96500 coulombs, Cu = 63.5).

  

Answers


John
63.5 g of Cu $\rightarrow$(96500 x 2)C

Thus 1.184 g Cu = ? $\frac{1.184\times 96500\times 2}{63.5}$ = 3598.6 C

But Q = It $\rightarrow$ 3598.6 = 2t $\rightarrow$ $\frac{3598.6}{2}$ = 1799.3 sec

= 29.988min or 30 minutes
johnmulu answered the question on February 18, 2017 at 11:37


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