Calculate the time in minutes required to deposit 1.184 g of copper if a current of 2 amperes was used. (1 Faraday = 96500 coulombs, Cu = 63.5).

Answers

63.5 g of Cu

$\rightarrow$ (96500 x 2)C

Thus 1.184 g Cu = ?

$\frac{1.184\times 96500\times 2}{63.5}$ = 3598.6 C

But Q = It

$\rightarrow$ 3598.6 = 2t

$\rightarrow$

$\frac{3598.6}{2}$ = 1799.3 sec

= 29.988min or 30 minutes

johnmulu answered the question on February 18, 2017 at 11:37

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