The capacity of a vessel is stated as 3000 millilitres to the nearest 10 millilitres. Find a. The limit within which the capacity lies. b. The percentage error

      

The capacity of a vessel is stated as 3000 millilitres to the nearest 10 millilitres. Find
a. The limit within which the capacity lies.
b. The percentage error

  

Answers


joseph
a. Absolute error is ½ (10 ml) = 5 ml
Lowest possible capacity 3000ml- 5ml = 2995 ml
Highest possible capacity 3000 ml + 5ml =3005ml
b. Percentage error = (absolute error /actual measure) x100%
= (5/3000) x100%
=.17%

joseph rimiru answered the question on November 11, 2017 at 06:48


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