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Light of frequency 7.5 x 1014Hz strikes a metal surface whose work function is 4.0 x 10-19 J. Determine the kinetic energy of the emitted photoelectrons.

      

Light of frequency 7.5 x 1014Hz strikes a metal surface whose work function is 4.0 x 10-19 J. Determine the kinetic energy of the emitted photoelectrons. (take planks constant h = 6.63 x 10-34Js)

  

Answers


John
hf = Wo + ke

Ke = hf - Wo = (6.63 x 10-34 x 7.5 x 1014) - 4.0 x 10-19

= 9.725 x 10-20 joules
johnmulu answered the question on February 21, 2017 at 13:03


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