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In a sample there are 5.12 x 1020 atoms of krypton -92 initially. If the half-life of krypton-92 is 3.0 s, determine the number of atoms that will have decayed after 6 s.

      

In a sample there are 5.12 x 1020 atoms of krypton -92 initially. If the half-life of krypton-92 is 3.0 s, determine the number of atoms that will have decayed after 6 s.

  

Answers


John
After 3 seconds, the number decayed

= $\frac{1}{2}$ x 5.12 x 1020 = 2.56 x 1020

Next 3 seconds, the number decayed = $\frac{1}{2}$ x 2.56 x 1020 = 1.28 x 1020

Total number decayed = (1.28 + 2.56) x 1020 = 3.84 x 1020
johnmulu answered the question on February 21, 2017 at 13:26


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