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a) Volume delivered from
6 – 8.30 am
6.16 x $\frac{10}{5}$ x $\frac{5}{2}$ x 60 x 60
Base area x height
= $\frac{6.16\times 10\times 5\times 60\times 60 }{2\times 100\times 100}$
L = $\frac{6.16\times 10\times 5\times 60\times 60}{3\times 2\times 100\times 100\times 100}$
h = 0.1848 m = 18.48 cm
b) Volume retained per second
= 6.16 x 10 – 11.6
= 61.6 – 11.6
= 50 cm3/s
30, 000 x 120 = 50 x t
$\frac{30, 000\times 120}{50}$ = t
t = 72 000 seconds
= $\frac{72 000}{60\times 60}$ = 20 hrs
Time to fill is
6. 00 +
20. 00
26. 00
- 24. 00
= 2.00 a.m the following days
johnmulu answered the question on March 2, 2017 at 12:13
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