Water flows through a circular pipe of cross-sectional area 6.16 cm² at a uniform speed of 10 cm/sec. At 6. 00 a.m water starts flowing through the pipe into an empty tank of base area 3 m².

Water flows through a circular pipe of cross-sectional area 6.16 cm² at a uniform speed of 10 cm/sec. At 6. 00 a.m water starts flowing through the pipe into an empty tank of base area 3 m².
a) What is the depth of the water in the tank at 8.30 a.m
b) If the tank is 1.2 m high, and a hole at the bottom through which water leaks at a rate of 11.6 cm ³ per second, determine the time at which the tank will be filled.

Answers

a) Volume delivered from

6 – 8.30 am

6.16 x $\frac{10}{5}$ x $\frac{5}{2}$ x 60 x 60

Base area x height

= $\frac{6.16\times 10\times 5\times 60\times 60 }{2\times 100\times 100}$

L = $\frac{6.16\times 10\times 5\times 60\times 60}{3\times 2\times 100\times 100\times 100}$

h = 0.1848 m = 18.48 cm

b) Volume retained per second

= 6.16 x 10 – 11.6

= 61.6 – 11.6

= 50 cm³/s

30, 000 x 120 = 50 x t

$\frac{30, 000\times 120}{50}$ = t

t = 72 000 seconds

= $\frac{72 000}{60\times 60}$ = 20 hrs

Time to fill is

6. 00 +
20. 00
26. 00
- 24. 00
= 2.00 a.m the following days

---

johnmulu answered the question on March 2, 2017 at 12:13

Next: ABCD is a parallelogram with A(1,1) and C(8, 10). The equation of AB is 4x - 5y = -1 and the equation of BC is 5x - 2y = 20. Determine
Previous: a) Divide 1 000 cm³ in the ratio of

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