The equation of a straight line L1 is given by 2y + 8x - 10 = 0. Another line L2 cuts L1 at right angles...

      

The equation of a straight line L1 is given by 2y + 8x - 10 = 0. Another line L2 cuts L1 at right angles such that the point of intersection of the two lines has coordinates (-3,k).
(a) Find the value of k
(b) Hence find the equation of L2

  

Answers


John
2y + 8x - 10 => y = 4x + 5

M1 = -1

L2g m2x - 4 = -1

M2 = + $\frac{1}{4}$

2k + 8 (-3) _+ 0

K = 17

G = $\frac{1}{4}$

$\frac{x - 17}{x - -3}$ = $\frac{1}{4}$

4y = x + 71

4y - x - 71 = 0
johnmulu answered the question on November 16, 2017 at 08:47


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