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Distance traveled by Hellina from 8 - 3.30 a.m.
= 64 x $\frac{1}{2}$ = 32 km
Distance between the
= 384 - 32 = 352 km
Time taken by Joyce to meet Hellima
= $\frac{352}{128}$ = 2$\frac{3}{4}$ hrs
Time they meet
= 8.30
2.45
= 11.15 am
b) Distance travelled by Joyce
64 x $\frac{11}{14}$ = 176 km
c) Distance travelled by Hellima from 8 - 10. 30 am
64 x 2 = 128 km
Distance between them
= 384 - (228 + 160)
= 384 - 288 = 96 km
johnmulu answered the question on March 2, 2017 at 12:53
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