x2 - xy - 12y2
P = -12, S = -1, N = 3, -4
(x - 4y)(x + 3)
therefore L.C.M of x2 - xy - 12y2
and x -4y is (x - 4y)(x + 3y)
= $\frac{7 - 1(x + 3y)}{x^2 - xy - 12y^2}$
= $\frac{7 - x - 3y}{(x - 4y)(x + 3y)}$
johnmulu answered the question on March 2, 2017 at 13:13
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