Find the L.C.M. of x² - xy - 12y² and x - 4y, Hence simplify

Find the L.C.M. of x² - xy - 12y² and x - 4y, Hence simplify

$\frac{7}{x^2 - xy + 12y^2}$ - $\frac{1}{x - 4y}$

Answers

x² - xy - 12y²

P = -12, S = -1, N = 3, -4

(x - 4y)(x + 3)

therefore L.C.M of x² - xy - 12y²

and x -4y is (x - 4y)(x + 3y)

= $\frac{7 - 1(x + 3y)}{x^2 - xy - 12y^2}$

= $\frac{7 - x - 3y}{(x - 4y)(x + 3y)}$

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johnmulu answered the question on March 2, 2017 at 13:13

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