If log2 = 0.3010, log3 = 0.4771 and log 5 = 0.6990, Find the logarithm of 3.3

Answers

Let x = 3.333 ....

10x = 33.33........

x =

$\frac{30}{9}$ ; x =

$\frac{10}{3}$

$\frac{log(5\times 2)}{log 3}$

= log 5 + log 2 - log 3

= 0.6990 + 0.3010 - 0.4771
= 0.5229

johnmulu answered the question on March 2, 2017 at 13:47

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