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Let x = 3.333 ....
10x = 33.33........
x = $\frac{30}{9}$; x = $\frac{10}{3}$
$\frac{log(5\times 2)}{log 3}$
= log 5 + log 2 - log 3
= 0.6990 + 0.3010 - 0.4771
= 0.5229
johnmulu answered the question on March 2, 2017 at 13:47
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