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Solve x – 3y = 4 and 3x + y = 2
3(x – 3y = 4)
3x + y = 2
3x – 9y = 12
3x + y = 2
-10y = 10; y = -1
Substitute y = - 1 in x – 3y = 4
X – 3(-1) = 4
x + 3 = 4; x = 1
Point intersection is (1, -1)
From 3x + 4y = 0; 4y = -3x
Y = -$\frac{3}{4}x$
For parallel lines m1 = m2
johnmulu answered the question on March 6, 2017 at 05:22
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