Find the equation of a straight line which passes through the point of intersection of lines x – 3y = 4 and 3x + y = 2

      

Find the equation of a straight line which passes through the point of intersection of lines x – 3y = 4 and 3x + y = 2 and is parallel to the line 3x + 4y = 0

  

Answers


John
Solve x – 3y = 4 and 3x + y = 2

3(x – 3y = 4)

3x + y = 2

3x – 9y = 12

3x + y = 2

-10y = 10; y = -1

Substitute y = - 1 in x – 3y = 4

X – 3(-1) = 4

x + 3 = 4; x = 1

Point intersection is (1, -1)

From 3x + 4y = 0; 4y = -3x

Y = -$\frac{3}{4}x$

For parallel lines m1 = m2
johnmulu answered the question on March 6, 2017 at 05:22


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