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From3x + 2y – 7 = 0
2y = -3x + 7; y = $\frac{3}{2}x$ + $\frac{7}{2}$
M1 = gradient = - $\frac{3}{2}$
From ax + 3y + 2 = 0
Y = - $\frac{a}{3}x$ - $\frac{3}{2}$
M2 = gradient = - $\frac{a}{3}$
For perpendicular lines
M1m2 = -1 therefore -$\frac{3}{2}$ x -$\frac{3}{2}$ x $\frac{a}{3}$ = -1
$\frac{3a}{6}$ = -1; 3a = -6; a = -2
johnmulu answered the question on March 6, 2017 at 05:40
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