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The lines 3x + 2y – 7 = 0 and ax + 3y + 2 = 0 Are perpendicular

      

The lines 3x + 2y – 7 = 0 and ax + 3y + 2 = 0
Are perpendicular

  

Answers


John
From3x + 2y – 7 = 0

2y = -3x + 7; y = $\frac{3}{2}x$ + $\frac{7}{2}$

M1 = gradient = - $\frac{3}{2}$

From ax + 3y + 2 = 0

Y = - $\frac{a}{3}x$ - $\frac{3}{2}$

M2 = gradient = - $\frac{a}{3}$

For perpendicular lines

M1m2 = -1 therefore -$\frac{3}{2}$ x -$\frac{3}{2}$ x $\frac{a}{3}$ = -1

$\frac{3a}{6}$ = -1; 3a = -6; a = -2
johnmulu answered the question on March 6, 2017 at 05:40


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