The lines 3x + 2y – 7 = 0 and ax + 3y + 2 = 0 Are perpendicular

The lines 3x + 2y – 7 = 0 and ax + 3y + 2 = 0
Are perpendicular

Answers

From3x + 2y – 7 = 0

2y = -3x + 7; y =

$\frac{3}{2}x$ +

$\frac{7}{2}$

M₁ = gradient = -

$\frac{3}{2}$

From ax + 3y + 2 = 0

Y = -

$\frac{a}{3}x$ -

$\frac{3}{2}$

M₂ = gradient = -

$\frac{a}{3}$

For perpendicular lines

M₁m₂ = -1 therefore -

$\frac{3}{2}$ x -

$\frac{3}{2}$ x

$\frac{a}{3}$ = -1

$\frac{3a}{6}$ = -1; 3a = -6; a = -2

johnmulu answered the question on March 6, 2017 at 05:40

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