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a) Number of litres bought
= $\frac{760}{x}$
b) Number of litres bought when the price was up
$\frac{760}{x + \frac{1}{4}}$ = $\frac{760}{\frac{4x + 1}{4}}$
= $\frac{760}{4x + 1}$
= $\frac{760}{x} - \frac{3040}{4x + 1}$ = 8
= $\frac{760(4x + 1) – x(3 040)}{x(4x + 1)}$ = 8
760 = 32x2 + 8x
95 = 4x2; + x
Therefore 4x2 + x – 95 = 0
c) 4x2 + x – 95 = 0
P = -380
S = 1
N = 20,-19
(4x2 - 19) (x + 5) = 0
4x – 19 = 0; 4x = 19
X = sh 4. 75
Price after the rise was
Sh 4. 75 + 0.25
= sh 5.00
johnmulu answered the question on March 6, 2017 at 05:48
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