Let Musyoka take x days
In 1 day Mutua cultivates $\frac{1}{15}$
In 1 day Musyoka cultivates $\frac{1}{x}$
In 1 day both had done
$\frac{1}{6}$ x 4 = $\frac{2}{3}$
Fraction of work remaining is
1 - $\frac{2}{3}$ = $\frac{1}{3}$
To complete the work
$\frac{1}{15}$ + $\frac{1}{x}$ = $\frac{1}{6}$; $\frac{1}{x}$ = $\frac{1}{6}$ - $\frac{1}{15}$; $\frac{1}{x}$ = $\frac{1}{10}$
x = 10 days: Musyoka alone would take 10 days to complete the work.
To complete the remaining $\frac{1}{3}$
Musyoka would take
$\frac{1}{10}x$ = $\frac{1}{3}$; x = $\frac{10}{3}$ = 3$\frac{1}{3}$ days
johnmulu answered the question on March 6, 2017 at 06:32
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