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i) the number of computers produced per day is
$\frac{600}{x}$
ii) The new number of computers produced is
$\frac{600}{x - 1}$
iii) If the difference between the two daily rates is 50 then
$\frac{600}{x - 1} - \frac{600}{x}$ = 50
$\frac{600x - 600x + 600}{x^2 - x}$ = 50
600 = 50x2 - 50x
50x2 - 50x - 600 = 0
It reduces to x2 - x - 12 = 0
iv) x2 - x - 12 = 0
P = -12; S = -1; N = -4,3
($x^2 - 4x $) + (3x - 12) = 0
x(x - 4) + 3(x -4) = 0
(x + 3) (x -4) = 0
x - 4 = 0; x = 4
the number of computers produced daily is
$\frac{600}{4}$ = 150 computers
johnmulu answered the question on March 6, 2017 at 08:29
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