Find the distance of the point (4,3) from the point of intersection of line 2x - 3y = 7 and 4x + 3y = 5

Find the distance of the point (4,3) from the point of intersection of line 2x - 3y = 7 and 4x + 3y = 5 (leave your answer in simplified surd form)

Answers

Solve the two equations

simultaneously

2x - 3y = 7
4x + 3y = 5

6x = 12, x = 2

Substitute in 2x - 3y = 7

4 - 3y = 7; -3y = 3

y =-1

Distance of point (2,-1) from (4,3)

Distance =

$\sqrt{(4 - 2)^2 + (3--1)^2}$

=

$\sqrt{4 + 16}$ =

$\sqrt20$

=

$\sqrt{4\times 5}$ = 2

$\sqrt5$

johnmulu answered the question on March 6, 2017 at 09:50

Next: Evaluate. $\frac{12.4\times \sqrt2}{(5^2 + 6 )\sqrt{0.125}}$
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