Three years ago a father was three times as old as his son. In three years time, the sum of their ages will be 76 years.

      

Three years ago a father was three times as old as his son. In three years time, the sum of their ages will be 76 years. Determine their present ages.

  

Answers


John
3 years ago: let son be x years

therefor = 3x years

now:

Son: (x + 3) years

Father: (3x + 3)years

3 years' time

Son: (x + 6) years

Father: (3x + 6) years

x + 6 + 3x + 6 = 76

4x + 12 = 76

4x = 64x = 16

present ages are

Son = 16 + 3 = 19 years

Father = (3 x 16 + 3)

= 48 + 3 = 51 years
johnmulu answered the question on March 6, 2017 at 12:03


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