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log(x + 5) = log($\frac{4}{x + 2}$)
$\frac{x + 5}{1}$ = $\frac{4}{x + 2}$
(x + 5)(x + 2) = 4
x2 + 2x + 5x + 10 = 4
x2 + 7x + 6 = 0
P = 6; S = 7; N = 6,1
(x + 6)(x + 1) = 0
x + 6 = 0 therefor = -6
or x + 1 = 0 therefor = -1
johnmulu answered the question on March 6, 2017 at 13:18
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