The dimensions of a rectangle are given as 8 cm by 5 cm. If A is the area of the rectangle and P is perimeter, determine the maximum possible value of

The dimensions of a rectangle are given as 8 cm by 5 cm. If A is the area of the rectangle and P is perimeter, determine the maximum possible value of
A $\div$ P.

Answers

Maximum possible value of

A

$\div$ P =

$\frac{Maximum\;of\;A}{Minimum\;of\;P}$

=

$\frac{8.5 \times 5.5}{2(7.5 + 4.5)}$

= 46.75/2(12)

=

$\frac{46.75}{2(12)}$ = 1.95

johnmulu answered the question on March 7, 2017 at 05:43

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