Get premium membership and access questions with answers, video lessons as well as revision papers.

The dimensions of a rectangle are given as 8 cm by 5 cm. If A is the area of the rectangle and P is perimeter, determine the maximum possible value of

      

The dimensions of a rectangle are given as 8 cm by 5 cm. If A is the area of the rectangle and P is perimeter, determine the maximum possible value of
A $\div$ P.

  

Answers


John
Maximum possible value of

A $\div$ P = $\frac{Maximum\;of\;A}{Minimum\;of\;P}$

= $\frac{8.5 \times 5.5}{2(7.5 + 4.5)}$

= 46.75/2(12)

= $\frac{46.75}{2(12)}$ = 1.95
johnmulu answered the question on March 7, 2017 at 05:43


Next: A bus P leaves Kisumu at 8 a.m travelling towards Nairobi at an average speed of 70 km/hr.
Previous: $\frac{\sqrt5 -2\sqrt3}{\sqrt2 + \sqrt{12}}$ is expression in surd form

View More Mathematics Questions and Answers | Return to Questions Index


Learn High School English on YouTube

Related Questions