i) The conjugate of the denominator in simplest form
= $\sqrt2 \; - \sqrt12 \; = \; \sqrt2 \; - \; \sqrt{4\times 3}$
= $\sqrt2 -2\sqrt3$
ii) $\frac{(\sqrt5 \; 2\sqrt3)}{(\sqrt2 \; 2\sqrt3)}$ x $\frac{(\sqrt2 \; -2\sqrt3)}{(\sqrt2 \; 2\sqrt3)}$
$\frac{\sqrt{10} - 2\sqrt{15} - 2\sqrt6 \; + 4\times 3}{2\; 2\sqrt6 + 2\sqrt6 - 4 x 3}$
$\frac{\sqrt{10}\; 2\sqrt{15} \; 2\sqrt6 \; 12}{-10}$
johnmulu answered the question on March 7, 2017 at 06:12
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