Let width be x
length = 1 200 - 2x
Area = x(1 200 - 2x)
A = 1 200x - 2x2
$\frac{dA}{dx}$ = 1 200 - 4x
For maximum area
$\frac{dA}{dx}$ = 0
1 200 - 4x = 0
x = 300 metres
Dimensions are:
width = 300 m
length = 600 m
johnmulu answered the question on March 7, 2017 at 07:01
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