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Nafula broke three beakers and 4 test tubes and Munyao broke two beakers and 5 test tubes during practicals in the laboratory. If Nafula was...

      

Nafula broke three beakers and 4 test tubes and Munyao broke two beakers and 5 test tubes during practicals in the laboratory. If Nafula was charged Sh 560 and Munyao Sh 490 for the breakages, find the cost of one beaker and one test tube.

  

Answers


ANNETTE
let the test tube be y and beakers be x

now 3x+4y=560
2x+5y=490
2(3x+4y=560) = 6x+8y=1120
3(2x+5y=490) = 6x+15y=1470

subtract 6x-6x=0
8y-15y=-7y
1120-1470=-350
thus -7y=-350, find y, y=-350/-7, y=50,
replace the value y 3x+4(50)=560, 3x+200=560
collect like terms 3x=560-200, 3x=360, x=120
so, one test tube cost ksh.50 and one beaker costs ksh.120
neptune answered the question on November 21, 2017 at 07:05


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