$\frac{2}{2 + \sqrt3}$ + $\frac{2\sqrt3}{2 -\sqrt3}$
= $\frac{2(2 -\sqrt3)+ 2\sqrt3 (2 +\; \sqrt3)}{(2 + \sqrt3)(2 \; \sqrt3)}$
= $\frac{4 - 2\sqrt3 + 4\sqrt3 + 2\times 3}{4 - 2\sqrt3 + 2\sqrt3 - 3}$
Combine the Like terms
= $\frac{4\; + 6\; + \; 2\sqrt3}{ 4 - 3}$
= 10 + 2$\sqrt3$ = a + b$\sqrt3$
a = 10 and b = 2
johnmulu answered the question on March 7, 2017 at 08:53
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