Solve the equation 4sin (2x + 30)o = -$\sqrt3$ in the range -90o < x <180o

      

Solve the equation
4sin (2x + 30)o = -$\sqrt3$ in the range -90o < x <180o

  

Answers


John
4 sin (2x + 30) = -$\sqrt3$

sin (2x + 30) = $\frac{\sqrt3}{4}$

sin (2x + 30) = - $\frac{1.732}{4}$

sin (2x + 30) = -0.433

sin-1 -0.433 = 25.7o

The angle lies in the third and forth quadrant

2x + 30 = 180 + 25.7o

2x = 175.7; x = 87.9o

2x + 30 = 360 - 25.7

2x = 304.3; x = 152.2o

2x + 30 = -25.7

2x = -55.7; x = -27.8o

2x = -55.7; x = -27.8o

x = 87.9 and 152.2
johnmulu answered the question on March 7, 2017 at 09:18


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