The equation of a curve is y = 3x2 -4x + 1, Find the gradient function of the curve and its value when x = 2

      

The equation of a curve is
y = 3x2 -4x + 1
a) Find the gradient function of the curve and its value when x = 2
b) Determine the equation of the tangent to the curve at(2,5)

  

Answers


John
a) Given y = 3x2 - 4x + 1

Gradient function is

$\frac{dy}{dx}$ = 6x - 4

Its value when x = 2 is 6 x 2 - 4 = 12 - 4 = 8

b) i) Equation of the tangent to the curve

at (2,5)

Take points (2,5)

and (x,y) whose gradient is 8

therefore $\frac{y - \;5}{x-\;2}$ = 8

y - 5 = 8x - 16

y = 8x - 16 + 5

y = 8x - 11
johnmulu answered the question on March 7, 2017 at 13:41


Next: a) The nth term of a sequence is given as 3(m + 1) - 2m.
Previous: The sides of triangles were measured and recorded as 8.4 cm, 10.5 cm and 15.3 cm. Calculate the percentage error in perimeter

View More Mathematics Questions and Answers | Return to Questions Index


Exams With Marking Schemes

Related Questions