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a) Given y = 3x2 - 4x + 1
Gradient function is
$\frac{dy}{dx}$ = 6x - 4
Its value when x = 2 is 6 x 2 - 4 = 12 - 4 = 8
b) i) Equation of the tangent to the curve
at (2,5)
Take points (2,5)
and (x,y) whose gradient is 8
therefore $\frac{y - \;5}{x-\;2}$ = 8
y - 5 = 8x - 16
y = 8x - 16 + 5
y = 8x - 11
johnmulu answered the question on March 7, 2017 at 13:41
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