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Equivalent solute=molar mass/basicity. 126/2=63equ^-1. mass of solute=3.15g. equivalent weight=mass/eq mass. 3.15g/63gequ^-1. 0.05equ. normality=eq of solute/volume. 0.05/0.25=0.2N
lily nekesa answered the question on November 21, 2017 at 10:46
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