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i) Distance in nautical miles
Distance
= speed x times
= 27 nm/hr x 120 hrs
= 3240 nm
b) In km
1 nm = 1.853 km
3 240 nm= ?
= 3240 x 1.853
= 6 003.72 km
= 6 004 km
b) Speed in kilometres per hour
= $\frac{Distance}{Time}$ = $\frac{6 003.72}{120}$
= 50.03 km/hr
c) A (5oN, 45oE), B(5oN, xoE) let
longitude difference be x
= $\frac{x}{360}$ x 2 x 3.142 x 6370 x cos5o
= 5 994
= $\frac{x}{360}$ x 2 x 3.142 x 6 370 x 0.996 = 5994
110.6x = 5 994; x = 5994
110.6x = 5 994; x = 54.1
longitude of B
= 99.1oE
position of B
= (5oN,99.1oE)
johnmulu answered the question on March 8, 2017 at 06:19
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