log3(x + 23) - log3(log232) = log3(9 - 2x)
log3(x + 23) - log3(5) = log3(9 -2x)
log3[$\frac{x\; +\; 23}{5}$] = log3(9 - 2x)
$\frac{x + 23}{5}$ = $\frac{9 -2x}{1}$
x + 23 = 45 - 10x
11x = 22;
x = 2
johnmulu answered the question on March 8, 2017 at 09:29
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