Intersection point of the lines of equations 2x – 3y = -29 and circle whose radius is 5 units. Find the equation of the circle

Answers

Point of intersection is got by solving the two equations

Simultaneously

2x – 3y = -29

3(3x + y) = 17)

2x – 3y = -29

9x + 3y = 51

Add the two equations

11x = 22; x = 2

Substitute x = 2 in

2(2) – 3y = -29; 4 – 3y = -29

-3y = -33 y = 11

Centre of the circle is (2,11)

And radius = 5 units

Equation of the circle is

(x - 2) ² + (y - 11) )² = 5)²

x² - 4x + 4 + y)² - 22y + 121 = 25

x² - 4x + 4 + y)² - 22y + 125 = 25

x² - 4x + 4 + y)² - 22y + 100 = 0

johnmulu answered the question on March 8, 2017 at 09:36

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