The positions of two towns X and Y are given to the nearest degree as X(45^oN, 10^oW) and Y(45^oN, 70^oW). Find

The positions of two towns X and Y are given to the nearest degree as X(45^oN, 10^oW) and Y(45^oN, 70^oW). Find
a) The difference in longitude
b) The distance between the towns in
ii) Nautical miles (1nm = 1.85 km and R = 6370 km)
ii) the local time at Y is 2.00 p.m

Answers

a) Difference in longitude is

70^o - 10^o = 60^o

b) i) X and Y lie on latitude 45^oN. This is distance along the parallel of latitude

therefor Distance between X and Y in Km is

$\frac{60^o}{360^o} x 2 x 3.142 x 6 370 cos 45^o$

$\frac{1}{6}$ x 2 x 3.142 x 6370

= 4 718 km to s.f

ii) Distance in nautical miles

1nm = 1.85 km
4 718 km

= $\frac{4 718}{1.85}$

= 2550 nm

---

johnmulu answered the question on March 8, 2017 at 13:40

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