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a) Open the brackets.
4x + 3y + 3z - z + 4y - 2x
Combine the like terms
4x - 2x + 3y + 4y + 3z - z
= 2x + 7y + 2z
b) Factorise the numerator to get
3(x - 3)(x + 3)
Therefore
$\frac{3(x^2 - 9)}{x + 3}$ = $\frac{3(x-3)}{}$
Reduces to 3(x-3) = 3x - 9.
johnmulu answered the question on March 9, 2017 at 06:44
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