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Solve for x in: $\frac{x-2}{3}$ - $\frac{3-x}{4}$ = $\frac{x-2}{2}$

Solve for x in:
$\frac{x-2}{3}$ - $\frac{3-x}{4}$ = $\frac{x-2}{2}$

Answers

-Multiply boy sides by the L.C.M

(12);

12($\frac{x-2}{3} - \frac{3-x}{4}) = (\frac{x-2}{2}$)12

4(x-2) -3(3-x) = 6(x-2)

4x – 8 – 9 + 3x = 6x – 12

7x -17 = 6x – 12

7x – 6x = 17 – 12 x = 5.

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johnmulu answered the question on March 10, 2017 at 04:55

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